0=-16x^2+50x-2

Solution for 0=-16x^2+50x-2 equation:

0=-16x^2+50x-2

We move all terms to the left:

0-(-16x^2+50x-2)=0

We add all the numbers together, and all the variables

-(-16x^2+50x-2)=0

We get rid of parentheses

16x^2-50x+2=0

a = 16; b = -50; c = +2;
Δ = b2-4ac
Δ = -502-4·16·2
Δ = 2372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2372}=\sqrt{4*593}=\sqrt{4}*\sqrt{593}=2\sqrt{593}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{593}}{2*16}=\frac{50-2\sqrt{593}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{593}}{2*16}=\frac{50+2\sqrt{593}}{32}
$